Question

Find the greatest number of three digits which is a perfect square.

Answer 1

We know that,

Greatest $3$-digits number $=999$

To find a greatest $3$-digit perfect square number, we need to find the smallest number subtracted from $999$. For that, lets find square root of $999$ by long division method.

While finding the square root, we've see that $38$ has been left.

$\therefore$ Perfect square $=999-38=961$

$\therefore$ Greatest $3$-digit perfect square $=961$