Question

Find the greatest number that will divide 121 , 33 and 55 leaving 1 , 3 and 5 respectvely , as remainder

Answer 1

$121-1=120=2\times 2\times 2\times 3\times 533-3=30=2\times 3\times 555-5=50=2\times 5\times 5$

H.C.F$(120,30,50)=2\times 5=10$

So, answer$=10$