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Question

Find the greatest number that will divide 132,242 and 382 leaving a remainder 2 in each case.


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Solution

Subtracting remainder from the given numbers.

Firstly, we have to subtract the remainder 2 from each number, so that each number is exactly divisible by the greatest number.

132-2=130242-2=240382-2=380

Finding the H.C.F of 130,240 and 380.

Prime factorisation of 130=2×5×13.

Prime factorisation of 240=2×2×2×2×3×5.

Prime factorisation of 380=2×2×5×19.

H.C.F of 130,240 and 380=2×5=10.

Hence, the answer of this question is 10.


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