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Question

Find the greatest number that will divide 28, 143, 303 leaving the same remainder of 3 in each case.


A

7

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B

6

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C

5

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D

8

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Solution

The correct option is C

5


Required number = HCF of {(28 - 3), (143 - 3), (303 - 3)}

= HCF of 25, 140, 300

First find the HCF of 25, 140

HCF of 25 and 140 is 5

Find the HCF of 5 and 300

5 is the HCF of 5 and 300.

Consequently, HCF of 25, 140 and 300 is 5.

Hence, the required number is 5.


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