Find the greatest number that will divide 28, 143, 303 leaving the same remainder of 3 in each case.
5
Required number = HCF of {(28 - 3), (143 - 3), (303 - 3)}
= HCF of 25, 140, 300
First find the HCF of 25, 140
∴ HCF of 25 and 140 is 5
Find the HCF of 5 and 300
5 is the HCF of 5 and 300.
Consequently, HCF of 25, 140 and 300 is 5.
Hence, the required number is 5.