wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the greatest number that will divide 28, 143, 303 leaving the same remainder of 3 in each case.


A

7

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

5


Required number = HCF of {(28 - 3), (143 - 3), (303 - 3)}

= HCF of 25, 140, 300

First find the HCF of 25, 140

HCF of 25 and 140 is 5

Find the HCF of 5 and 300

5 is the HCF of 5 and 300.

Consequently, HCF of 25, 140 and 300 is 5.

Hence, the required number is 5.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
HCF
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon