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Question

Find the greatest number which can divide 257 and 329 so as to leave a remainder 5 in each case.

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Solution

Let x=257
y=329
Given R=5
x5=2575=252
y5=3295=324
Factorize 252 and 324
252=22×32×7
324=22×34
Required number will be the HCF of 324 and 252
HCF=22×32=4×9=36.

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