Find the greatest number which divides 120, 165 and 210 exactly leaving remainders 5, 4 and 3 respectively
A
7
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B
5
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C
23
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D
None of these
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Solution
The correct option is D None of these The required number will be the H.C.F of (120 - 5), (165 - 4) and (210 - 3) i.e. H.C.F. of 115 161 and 207 ∴ Required number = H.C.F. of 115, 161 and 207 = 23