Question

Find the greatest number which divides 120, 165 and 210 exactly leaving remainders 5, 4 and 3 respectively

• A. 7
• B. 5
• C. 23
• D. None of these

Answer 1

The correct option is D None of these

The required number will be the H.C.F of (120 - 5), (165 - 4) and (210 - 3) i.e. H.C.F. of 115
161 and 207
$\therefore$ Required number = H.C.F. of 115, 161 and 207 = 23