Find the greatest weight which can be contained exactly in 3 kg 7 hg 8 dag 1 g and 9kg 1hg 5dag 4g.

1

9

dag

9

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1

8

dag

9

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2

8

dag

8

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2

9

dag

9

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Solution

The correct option is A $1$ hg $9$ dag $9$ g
$3 k g 7 h g 8 d a g 1 g = 3781$
$9 k g 1 h g 5 d a g 4 g = 9154$
The greatest weight required is G.C.F. of $3781$ and $9154$
Using Euclid algorithm
$9154 = 3781 \times 2 + 1592$
$3781 = 1592 \times 2 + 597$
$1592 = 597 \times 2 + 398$
$597 = 398 \times 1 + 199$
$398 = 199 \times 2 + 0$
Hence greatest weight $= 1 h g 9 d a g 9 g$

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