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Question

Find the H.C.F and L.C.M of the polynomial whose p(x)=x25x+6 and q(x)=x2+5x+4.

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Solution

Given:
p(x)=x25x+6
q(x)=x2+5x+4
Factor of x2+5x+4=(x+1)(x+4)
Factor of x25x+6=(x2)(x3)
So, H.C.F of p(x) and q(x)= (x+1)
Using the formula,
p(x)×q(x)= H.C.F × L.C.M
L.C.M=(x+1)(x+4)(x2)(x3)(x+1)x+1)
=(x+1)(x+4)(x2)(x3)
Therefore, L.C.M is (x+1)(x+4)(x2)(x3).

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