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Question

Find the H.C.F. of 180,252 and 324 using Euclid division of lemma.

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Solution

Let us find HCF of 180 and 252 using Euclid's division algorithm.
252=180×1+72
180=72×2+36
72=36×2+0

Thus, HCF(180,252)=36.

Now, we find the HCF of 36 and third number 324.

We have,
324=36×9+0

I.e., HCF(36,324)=36

Hence, the required HCF=36.

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