Find the H.C.F of 420 and 130 by iterative division method.

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Solution

The correct option is C 10
To find the HCF of the numbers,
$420 = 130 \times 3 + 30$
$130 = 30 \times 4 + 10$
$30 = 10 \times 3 + 0$
The last divisor is 10.
So, the HCF of 420 and 130 is 10.

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