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Question

Find the H.C.F of the expressions x3+(a+b)x2+(ab+1)x+b and x3+2ax2+(a2+1)x+a.

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Solution

We find factors of both polynomials :
x3+(a+b)x2+(ab+1)x+b
x3+ax2+bx2+abx+x+b
x3+ax2+x+bx2+abx+b
x(x2+ax+1)+b(x2+ax+1)
(x+b)(x2+ax+1)
x3+2ax2+a2x+x+a
x3+ax2+x+ax2+a2x+a
(x2+ax+1)+a(x2+ax+1)
(x+a)(x2+ax+1)
HCF of x3+(a+b)x2(ab+1)+b and x3+2ax2+(a2+1)x+a
=x2+ax+1

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