Find the $H . C . F$ of the following monomials.
$15 a^{2} - 45 a^{2}, 150 a$

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Solution

$\begin{matrix} 15 a^{2} - 45 a^{2} = 15 a^{2} (1 - 3) = - 30 a^{2} = - 2 \times 3 \times 5 \times a \times a^{2} 150 a = 2 \times 3 \times 5 \times 5 \times a H . C . F = 30 a \end{matrix}$

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