Question

Find the H.C.F of the following numbers.

$\frac{4}{9},\frac{16}{45}$ and $\frac{64}{81}$

• A. $\frac{4}{405}$
• B. $\frac{16}{81}$
• C. $\frac{4}{81}$
• D. None of these
  

Answer 1

The correct option is A $\frac{4}{405}$

HCF of 4, 16 and 64 = 4

For LCM of 9, 45, 81

$9=3\times 345=3\times 3\times 581=3\times 3\times 3\times 3So,LCM=3\times 3\times 3\times 3\times 5=405$

So, HCF of $\frac{4}{9},\frac{16}{45}and\frac{64}{81}is\frac{4}{405}$

So, correct answer is option A.