Find the H.C.F. of (x2+x+1) and (x4+x2+1) by using the division method.
A
x2+x+1
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B
x2+x−1
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C
x2−x+1
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D
x2+2x+1
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Solution
The correct option is Ax2+x+1 x2+x+1)x4+0x3+x2+1(x2−x+1x4+x3+x2−−−––––––––––––––––−x3+0x2+0x+1−x3−x2−x+++––––––––––––––––x2+x+1x2+x+1−−−––––––––––––––0