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Question

Find the H.C.F. of (x2+x+1) and (x4+x2+1) by using the division method.

A
x2+x+1
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B
x2+x1
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C
x2x+1
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D
x2+2x+1
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Solution

The correct option is A x2+x+1
x2+x+1)x4+0x3+x2+1(x2x+1 x4+x3+x2 –––––––––––––– x3+0x2+0x+1 x3x2x + + + –––––––––––––– x2+x+1 x2+x+1 –––––––––––– 0

Therefore, H.C.F =x2+x+1

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