Question

Find the harmonic mean of the given numbers

$\frac{1}{2},\frac{1}{4},\frac{1}{6}$

• A. $\frac{36}{11}$
• B. $\frac{1}{4}$
• C. $\frac{21}{36}$
• D. $\frac{4}{1}$

Answer 1

The correct option is B

$\frac{1}{4}$

Given numbers are $\frac{1}{2},\frac{1}{4},\frac{1}{6}$.

We know harmonic mean for the numbers $a_1,a_2,a_3,........,a_n$ is

$\text{harmonic mean}=\frac{n}{\frac{1}{a_1}+\frac{1}{a_2}+\frac{1}{a_3}+...........+\frac{1}{a_n}}$

Let the harmonic mean for given numbers is y.

$⟹y=\frac{3}{2+4+6}$

$=\frac{3}{12}$

$=\frac{1}{4}$

So, the harmonic mean for the $\frac{1}{2},\frac{1}{4},\frac{1}{6}$ numbers is $\frac{1}{4}$