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Question

Find the HCF and LCM of 24a5b5c4,30a3b4c3,36a2b3c5

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Solution

The given monomials 24a5b5c4, 30a3b4c3 and 36a2b3c5 can be factorised as follows:

24a5b5c4=2×2×2×3×a×a×a×a×a×b×b×b×b×b×c×c×c×c

30a3b4c3=2×3×5×a×a×a×b×b×b×b×c×c×c

36a2b3c5=2×2×3×3×a×a×b×b×b×c×c×c×c×c

We know that HCF is the highest common factor, therefore, the HCF of 24a5b5c4, 30a3b4c3 and 36a2b3c5 is:

HCF=2×3×a×a×b×b×b×c×c×c=6a2b3c3

Also, the LCM is the least common multiple, therefore, the LCM of 24a5b5c4, 30a3b4c3 and 36a2b3c5 is:

LCM=2×2×2×3×3×5×a×a×a×a×a×b×b×b×b×b×c×c×c×c×c=360a5b5c5

Hence, the HCF is 6a2b3c3 and LCM is 360a5b5c5.

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