Find the HCF of 360 and 18144 by prime factorization.

$2 \times 3 \times 5 \times 7$

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$2^{3} \times 3^{4}$

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$2^{5} \times 3^{2}$

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$2^{3} \times 3^{2}$

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Solution

The correct option is D
$2^{3} \times 3^{2}$

By prime factorisation,
360 = $2^{3} \times 3^{2} \times 5$
18144 = $2^{5} \times 3^{4} \times 7$

$\Rightarrow$ HCF = $2^{3} \times 3^{2}$

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