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Question

Find the HCF of 8ab3,4a2b2, and 6a3b.

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Solution

8ab3=2×2×2×a1×b3
=23×a1×b3

4a2b2=2×2×a2×b2
=22×a2×b2

6a3b=2×3×a3×b
=21×31×a3×b1

To find the HCF of the three terms we will multiply each factor with the lowest power which is present in all three terms. So,
HCF=21×a1×b1
=2ab

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