Question

Find the $HCF$ of $8a{b}^3,4a^2{b}^2$, and $6a^{3}b.$

Answer 1

$8a{b}^3=2\times 2\times 2\times a^1\times b^3$

$=2^3\times a^1\times b^3$

$4a^2{b}^2=2\times 2\times a^2\times b^2$

$=2^2\times a^2\times b^2$

$6a^{3}b=2\times 3\times a^3\times b$

$=2^1\times 3^1\times a^3\times b^1$

To find the $HCF$ of the three terms we will multiply each factor with the lowest power which is present in all three terms. So,

$HCF=2^1\times a^1\times b^1$

$=2ab$