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Question

Find the HCF of the following algebraic expressions.
5x2y2, 15x2y2, 3xy2

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Solution

We first factorize the given algebraic expressions 5x2y2,15x2y2 and 3xy2 as shown below:

5x2y2=5×x×x×y×y15x2y2=3×5×x×x×y×y3xy2=3×x×y×y

The common factors of 5x2y2,15x2y2 and 3xy2 are x and y2, therefore, the HCF is:

x×y×y=xy2

Hence, the HCF of 5x2y2,15x2y2 and 3xy2 is xy2.

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