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Byju's Answer
Standard X
Mathematics
GCD of Polynomials
Find the HCF ...
Question
Find the HCF of the following algebraic expressions.
5
x
2
y
2
,
15
x
2
y
2
,
3
x
y
2
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Solution
We first factorize the given algebraic expressions
5
x
2
y
2
,
15
x
2
y
2
and
3
x
y
2
as shown below:
5
x
2
y
2
=
5
×
x
×
x
×
y
×
y
15
x
2
y
2
=
3
×
5
×
x
×
x
×
y
×
y
3
x
y
2
=
3
×
x
×
y
×
y
The common factors of
5
x
2
y
2
,
15
x
2
y
2
and
3
x
y
2
are
x
and
y
2
, therefore, the HCF is:
x
×
y
×
y
=
x
y
2
Hence, the HCF of
5
x
2
y
2
,
15
x
2
y
2
and
3
x
y
2
is
x
y
2
.
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