Find the HCF of the following numbers :
$18, 60$

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Solution

$18, 60$
$18 = 1, 2, 3, 6, 9, 18$
$60 = 1, 2, 3, 4, 6, 10, 12, 15, 30, 60$
Common factors = $1, 2, 3, 6$
$∴$ H.C.F. of $18$ & $60$ is $6$

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