Find the HCF of the following numbers :
$34, 102$

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Solution

$34$ & $102$
$34 = 1, 2, 17, 34$
$102 = 1, 2, 3, 6, 17, 34, 51, 102$
$∴$ common factors = $1, 2, 17, 34$
$∴$ H.C.F. of $34$ & $102$ is $34$ .

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