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Question

Find the HCF of the following pair if polynomials:
a3+125 and a225

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Solution

We know that HCF is the highest common factor.

Factorise a3+125 as follows:

a3+125=a3+53=(a+5)[a2+52(a×5)]=(a+5)(a2+255a)
(using identity a3+b3=(a+b)(a2+b2ab))

Now, factorise a225 as follows:

a225=(a+5)(a5) (using identity a2b2=(a+b)(ab))

Since the common factor between the polynomials a3+125 and a225 is (a+5).

Hence, the HCF is (a+5).

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