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Question

Find the HCF of the following polynomials.
P(x) = 8(x416)
Q(x) = 12(x38)

A
4(x2)
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B
12(x2)
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C
(x2)(x2+2x+4)
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D
(x2+4)
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Solution

The correct option is A 4(x2)
P(x) = 8(x416)=23(x24)(x2+4)=23(x2)(x+2)(x2+4)
Q(x) =12(x38)=22× 3× (x2)(x2+2x+4)

The common irreducible factors of P(x) and Q(x) are 2 and (x-2)
The smallest exponents of these factors in P(x) and Q(x) are 2 and 1 respectively.

Hence, the HCF = 22× (x2)=4(x2).

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