Question

Find the HCF using prime factorisation method .

$224$ , $308$ and $330$

Answer 1

Given , the numbers are $224$ , $308$ and $330$

The prime factors of $224$ are $=2\times 2\times 2\times 2\times 2$

and prime factors of $308$ are $=2\times 2\times 7\times 11$

and prime factors of $330$ are $=2\times 3\times 5\times 11$

Now , HCF of numbers $224$ , $308$ and $330$ are $=2$

$=2$

Hence , the required HCF is $2$ .