Question

Find the HCF using the common factor method .

$36,$$30$ and $120$

Answer 1

Given , the numbers are $36,$$30$ and $120$

The prime factors of the number $36$ are $=1\times 2\times 2\times 3\times 3$

The prime factors of the number $30$ are $=1\times 2\times 3\times 5$

The prime factors of the number $120$ are $=1\times 2\times 2\times 2\times 3\times 5$

HCF of the numbers $36,$$30$ and $120$ are $=1\times 2\times 3$

$=6$

Hence, the required HCF is $6$ .