Find the heat lost by a copper cube of mass 400 g when it cools from 100 -C to 30 -C- Specific of heat of copper - 390 J kg -1 - C -1-

The correct option is B 10920 J Given , #160; m=400g=0.4kg , #160;θ_1=100^0C , θ_2=30^0C We have , specific heat of copper c=390J/kg ^oC No ...

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Standard XII

Physics

Throwing and Catching at Same Height

Find the heat...

Question

Find the heat lost by a copper cube of mass $400 g$ when it cools from $100^{\circ} C$ to $30^{\circ} C$ . (Specific of heat of copper $= 390 J$ ${k g}^{- 1}$ $^{\circ} C^{- 1}$ )?

50000 J

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10000 J

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10920 J

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10900 J

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Solution

The correct option is B $10920 J$
Given , $m = 400 g = 0.4 k g, θ_{1} = 100^{0} C, θ_{2} = 30^{0} C$
We have , specific heat of copper $c = 390 J / k g -^{o} C$
Now , heat lost by copper cube is given by the definition of specific heat c ,
$Q = m c Δ θ = m c (θ_{1} - θ_{2})$
or $Q = 0.4 \times 390 \times (100 - 30) = 10920 J$

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The heat released by a copper ball of mass 1 kg when cooled from 100°C to 90°C is 8.4 kJ. Calculate the specific heat capacity of copper.

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. It is dropped in a copper calorimeter of mass

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, containing

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. The temperature of water rises to a steady state at

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= 4.18 \times 10^{3} J k g^{- 1}^{o} C^{- 1}

, specific heat of copper

0.386 \times 10^{3} J k g^{- 1}^{o} C^{- 1}

Q. What quantity of heat would be given out by

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of copper in cooling from

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20^{\circ} C

(Specific heat of copper = 0.09

{c a l g}^{- 1}

^{\circ} C^{- 1}

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C .$ If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is:

(Given: ${Specific heat of copper = 420 Joule kg}^{- 1}^{\circ} C^{- 1}$ , ${Specific heat of water = 4200 Joule kg}^{- 1}^{\circ} C^{- 1}$ )

50 g

of copper is heated to increase its temperature by

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. If the same quantity of heat is given to

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Specific heat of water

= 4186 J k g^{- 1} K^{- 1}

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Find the heat lost by a copper cube of mass 400g when it cools from 100∘C to 30∘C. (Specific of heat of copper =390J kg−1∘C−1)?

The correct option is B 10920JGiven , m=400g=0.4kg,θ1=1000C,θ2=300CWe have , specific heat of copper c=390J/kg−oCNow , heat lost by copper cube is given by the definition of specific heat c , Q=mcΔθ=mc(θ1−θ2)or Q=0.4×390×(100−30)=10920J

Find the heat lost by a copper cube of mass $400 g$ when it cools from $100^{\circ} C$ to $30^{\circ} C$ . (Specific of heat of copper $= 390 J$ ${k g}^{- 1}$ $^{\circ} C^{- 1}$ )?