Find the height from the surface of the moon where the value of 'g' is equal to the value of 'g' at a height of 57600 km from the surface of the earth. (Take mass M_E = 6 × 10²⁴ kg. Mass of the moon, M_m = 7.3 × 10²² kg, R_E = 6400 and radius of the moon, R_m = 1740 km)

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$T h e v a l u e o f a c c e l e r a t i o n d u e t o g r a v i t y a t h i g h t h i s g i v e n a s g = \frac{G M}{{(R + h)}^{2}} T h e v a l u e o f g i s e q u a l a t h e i g h t h_{E} f r o m e a r t h' s s u r f a c e a n d h_{M} f r o m t h e s u r f a c e o f m o o n . g = \frac{G M_{E}}{{(R_{E} + h_{E})}^{2}} = \frac{G M_{M}}{{(R_{M} + h_{M})}^{2}} \frac{6 \times 10^{24}}{{(6400 + 57600)}^{2}} = \frac{7.3 \times 10^{22}}{{(1740 + h_{M})}^{2}} \frac{600}{{(64000)}^{2}} = \frac{7.3}{{(1740 + h_{M})}^{2}} {(1740 + h_{M})}^{2} = 49834666.6666 (1740 + h_{M}) = 7059.3673 h_{M} = 5319 . 36 k m$

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Find the height from the surface of the moon where the value of 'g' is equal to the value of 'g' at a height of 57600 km from the surface of the earth. (Take mass ME = 6 × 1024 kg. Mass of the moon, Mm = 7.3 × 1022 kg, RE = 6400 and radius of the moon, Rm = 1740 km)

Find the height from the surface of the moon where the value of 'g' is equal to the value of 'g' at a height of 57600 km from the surface of the earth. (Take mass M_E = 6 × 10²⁴ kg. Mass of the moon, M_m = 7.3 × 10²² kg, R_E = 6400 and radius of the moon, R_m = 1740 km)