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Standard IX

Physics

Variation of Atmospheric Pressure with Altitude.

Find the heig...

Question

Find the height $h_{2}$ of the water in the long tube above the top initially.

\frac{3 p_{0}}{ρ g} - \frac{h_{0}}{3}

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\frac{2 p_{0}}{ρ g} - \frac{h_{0}}{2}

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\frac{{2 p}_{0}}{ρ g} - h_{0}

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\frac{p_{0}}{2 ρ g} - {2 h}_{0}

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Solution

The correct option is C $\frac{{2 p}_{0}}{ρ g} - h_{0}$
$2 P_{0} = h_{2} ρ g + h_{0} ρ g$ ( Liquid at same level have same pressure)
$h_{2} ρ g = 2 P_{0} - h_{0} ρ g$
$h_{2} = \frac{2 P_{0}}{ρ g} - h_{0}$

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Find the height h2 of the water in the long tube above the top initially.

The correct option is C 2p0ρg−h02P0=h2ρg+h0ρg ( Liquid at same level have same pressure)h2ρg=2P0−h0ρgh2=2P0ρg−h0

Find the height $h_{2}$ of the water in the long tube above the top initially.

The correct option is C $\frac{{2 p}_{0}}{ρ g} - h_{0}$
$2 P_{0} = h_{2} ρ g + h_{0} ρ g$ ( Liquid at same level have same pressure)
$h_{2} ρ g = 2 P_{0} - h_{0} ρ g$
$h_{2} = \frac{2 P_{0}}{ρ g} - h_{0}$