Find the height of a parallelogram whose area is $54 c m^{2}$ and the base is $15 c m$ .

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Solution

Area of a parallelogram $A =$ base $\times$ height
$\Rightarrow A = b \times h$
$\Rightarrow h = \frac{A}{b} = \frac{54}{15} = 3.6 ‬$ cms
$∴$ height of the parallelogram $= 3.6$ cms.

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Find the height of a parallelogram whose area is 54 cm2 and the base is 15 cm.

Area of a parallelogramA=base×height⇒A=b×h⇒h=Ab=5415=3.6‬cms∴ height of the parallelogram =3.6cms.

Find the height of a parallelogram whose area is $54 c m^{2}$ and the base is $15 c m$ .

Area of a parallelogram $A =$ base $\times$ height
$\Rightarrow A = b \times h$
$\Rightarrow h = \frac{A}{b} = \frac{54}{15} = 3.6 ‬$ cms
$∴$ height of the parallelogram $= 3.6$ cms.