Find the height of a right angled triangle if it's area is $22$ $m^{2}$ and its base is $2 m$ .

10 m

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44 m

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2 m

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22 m

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Solution

The correct option is D $22 m$
Area of right angled $Δ = \frac{1}{2} \times b a s e \times h e i g h t = 22 m^{2}$
$\Rightarrow \frac{1}{2} \times 2 \times h e i g h t = 22 \Rightarrow h e i g h t = 22 m$

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Find the height of a right angled triangle if it's area is 22 m2 and its base is 2m.

The correct option is D 22mArea of right angled Δ=12×base×height=22m2⇒12×2×height=22⇒height=22m

Find the height of a right angled triangle if it's area is $22$ $m^{2}$ and its base is $2 m$ .

The correct option is D $22 m$
Area of right angled $Δ = \frac{1}{2} \times b a s e \times h e i g h t = 22 m^{2}$
$\Rightarrow \frac{1}{2} \times 2 \times h e i g h t = 22 \Rightarrow h e i g h t = 22 m$