Question

Find the height of a trapezium that has parallel sides of $6\text{cm}$ and $8\text{cm}$, and an area of $49{\text{cm}}^2$.

• A. $4\text{cm}$
• B. $5\text{cm}$
• C. $3\text{cm}$
• D. $7\text{cm}$

Answer 1

The correct option is D $7\text{cm}$

Here, the parallel sides are $6\text{cm}$ and $8\text{cm}$.
So, $a=6\text{cm},b=8\text{cm}$
Area of the trapezium $=\frac{1}{2}(a+b)\times h$
So, $49=\frac{1}{2}\times (6+8)\times h$
$49=\frac{1}{2}\times (14\times h)$
$49=7\times h$
$h=7\text{cm}$