Question

Find the height of a trapezium whose area is $68{cm}^2$ and whose bases are $13cm$ and $26cm.$

• A. $\frac{68}{39}cm$
• B. $\frac{9}{8}cm$
• C. $\frac{10}{3}cm$
• D. $\frac{9}{5}cm$

Answer 1

The correct option is A $\frac{68}{39}cm$

we know

Area of Trapezium $=$ (sum of parallel sides)$\times$ (distance between them)

$68=(13+26)\times ($ height $)$

$\therefore$ Height $=\frac{68}{39}$ Answer