Find the height of a triangle having an area of $72 c m^{2}$ and base $16 c m$ .

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Solution

Height of a triangle $= 2 \times$ (Area $\div$ Base)
Here, base $= 16 c m$ and area $= 72 c m^{2}$
$∴$ Height $= 2 \times \frac{72}{16} = 9 c m$

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Find the height of a triangle having an area of 72cm2 and base 16cm.

Height of a triangle =2× (Area ÷ Base)Here, base =16cm and area =72cm2∴ Height =2×7216=9cm

Find the height of a triangle having an area of $72 c m^{2}$ and base $16 c m$ .

Height of a triangle $= 2 \times$ (Area $\div$ Base)
Here, base $= 16 c m$ and area $= 72 c m^{2}$
$∴$ Height $= 2 \times \frac{72}{16} = 9 c m$