Question

Find the height of an acute angle triangle of area 400 ${\text{m}}^2$, if the base of a triangle is 20 m.

• A. 80 m
• B. 10 m
• C. 20 m
• D. 40 m

Answer 1

The correct option is D 40 m

Given,
Area of a triangle $=400{\text{m}}^2$
Base of a triangle$=BC=20m$

Let height of a triangle be $=AD=hm$

Let consider a triangle $\Delta ABC$ as shown.
Here $BC=20m$ and $AD=hm$

As we know,
$\text{Area of}△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$

$400=\frac{1}{2}\times 20\times h$

$h=\frac{400\times 2}{20}=40m$

Option (d) is correct.