Question

Find the height of an equilateral triangle whose side is $6$ units.

Answer 1

Area of equilateral triangle $=\frac{\sqrt{3}}{4}{a}^2=\frac{\sqrt{3}}{4}\times 36=9\sqrt{3}$

Also area of triangle $=\frac{1}{2}\times$ height $\times$ base

$9\sqrt{3}=\frac{1}{2}\times 6\times$ height, here base of the triangle is 6 units

$\therefore$ height $=3\sqrt{3}$