Find the height of cone , whose volume is numerically equal to it's surface area

h = 3 (\frac{l}{r} + 1)

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h = 3 (\frac{l}{r} - 1)

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2

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I n f i n i t e

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Solution

The correct option is A $h = 3 (\frac{l}{r} + 1)$
Volume = surface area
$\Rightarrow \frac{1}{3} π r^{2} h = π r (l + r)$
$\Rightarrow \frac{1}{3} r h = l + r$
$\Rightarrow h = 3 (\frac{l}{r} + 1)$
Hence, solved.

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Find the height of cone , whose volume is numerically equal to it's surface area

The correct option is A h=3(lr+1)Volume = surface area ⇒13πr2h=πr(l+r)⇒13rh=l+r⇒h=3(lr+1)Hence, solved.

The correct option is A $h = 3 (\frac{l}{r} + 1)$
Volume = surface area
$\Rightarrow \frac{1}{3} π r^{2} h = π r (l + r)$
$\Rightarrow \frac{1}{3} r h = l + r$
$\Rightarrow h = 3 (\frac{l}{r} + 1)$
Hence, solved.