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Question

Find the height of the center of mass of the equilateral triangular lamina from the side AB as shown in figure. Given, side of the triangular lamina is 3 m.


A
3 m
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B
32 m
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C
32 m
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D
23 m
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Solution

The correct option is C 32 m
Given, side of the equilateral triangular lamina is 3 m.
In this case, triangular lamina is symmetric about y axis. So, x co-ordinate of COM of the triangular lamina is 0.


We know that, y-coordinate of COM is at 13rd of height from the base i.e 13×3a2

Position of COM of the triangular lamina is given by (xCOM,yCOM)=(0,a23)
So, required height (H) of COM above AB is equal to a23
H=a23=323 m=32 m.

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