Question

Find the height of the trapezium having area as 36 $c{m}^2$ and parallel sides as 10 $cm$ and 8 $cm$.
(2 marks)

Answer 1

Area of a trapezium $=\frac{1}{2}(\text{sum of parallel sides)}\times \text{height}$
(1 mark)

Let 'h' be the height of the trapezium.

$\Rightarrow \text{Area}=\frac{1}{2}\times (10+8)\times h=36$

$\Rightarrow \frac{1}{2}\left(18\right)\times h=36$

$\Rightarrow 9h=36$

$\Rightarrow h=4cm$
(1 mark)