Question

Find the height of the trapezium having area as 72 $c{m}^2$ and parallel sides as 12 $cm$ and 6 $cm$.
(2 marks)

Answer 1

Area of a trapezium $=\frac{1}{2}(\text{sum of parallel sides)}\times \text{height}$
(1 mark)

Let 'h' be the height of the trapezium.

$\Rightarrow \text{Area}=\frac{1}{2}\times (12+6)\times h=72$

$\Rightarrow \frac{1}{2}\left(18\right)\times h=72$

$\Rightarrow 9h=72$

$\Rightarrow h=8cm$
(1 mark)