Question

Find the height of the triangle having an area of $72c{m}^2$ and base $16cm.$

Answer 1

From the question is given that,
Area of the triangle $=72c{m}^2$
Base of the triangle $=16cm$
$\therefore$ Area of the triangle $=\frac{1}{2}\times base\times height$
$72=\frac{1}{2}\times 16\times height$
$72=1\times 8\times height$
$Height=\frac{72}{8}$
$Height=9cm$
Hence, the height of the triangle is $9cm.$