Find the height of the water level h2 (in situation 2), for which the block remains in its original position without the application of any external force
A
h/3
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B
4h/9
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C
2h/3
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D
h
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Solution
The correct option is C4h/9 Area of the hole =π(2r)2=4πr2 Area of the block =π(4r)2=16πr2 Area of the lower face in contact with liquid =16πr2−4πr2=12πr2 The block will not move if the upthrust U equals the weight W of the block ⇒ρgh2×12πr2=ρ3×(h×16πr2)×g⇒h2=4h9