Find the highest power of 3 contained in 120!

57

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60

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59

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58

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Solution

The correct option is D $58$
Highest power of 3 contained in 120!
$= ⌊ \frac{120}{3} ⌋ + ⌊ \frac{120}{3^{2}} ⌋ + ⌊ \frac{120}{3^{3}} ⌋ + ⌊ \frac{120}{3^{4}} ⌋ + ⌊ \frac{120}{3^{5}} ⌋$
$= 40 + 13 + 4 + 1 + 0$
$= 58$

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