Question

Find the hypotenuse of a right angled triangle whose perpendicular sides are $\sqrt{6}$ cm and $\sqrt{3}$ cm.

Answer 1

Given: perpendicular sides of a right angled triangle are $\sqrt{6}$ and $\sqrt{3}$.

Using Pythagoras theorem,

Hypotenuse = $\sqrt{{\sqrt{6}}^2+{\sqrt{3}}^2}$

= $\sqrt{6+3}$

= $\sqrt{9}$ cm

= 3 cm (1 mark)