Image of the point (2,1) must lie on the perpendicular from (2,1) on x+y-5=0 and at equal distance as of (2,1) from the mirror ..............1
Equation of perpendicular from (2,1) on given mirror , x-y-1=0 ................2
Let us assume coordinate of image to be (h,h-1) (Using 1 and 2)
Now midpoint of (2,1) and (h,h-1) must lie on mirror(Using 1) i.e should satisfy equation of mirror , which gives h=4 .
Thus coordinate of image is (4,3)