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Standard VI

Mathematics

Formation of an Expression

Find the imag...

Question

Find the image of the point $(- 2, - 7)$ under the transformation
$(x, y) \to (x - 2 y, - 3 x + y) .$

(12, - 1)

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(- 12, 1)

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(2, 7)

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(- 2, 7)

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Solution

The correct option is A $(12, - 1)$
Given transformation is
$(x, y) \to (x - 2 y, - 3 x + y)$
So, the point $(- 2, - 7)$ $\to (- 2 - 2 (- 7), - 3 (- 2) - 7)$
So, the image of the point $(- 2, - 7)$ under the given transformation is $(12, - 1)$

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Find the image of the point (−2,−7) under the transformation(x,y)→(x−2y,−3x+y).

The correct option is A (12,−1)Given transformation is (x,y)→(x−2y,−3x+y)So, the point (−2,−7) →(−2−2(−7),−3(−2)−7)So, the image of the point (−2,−7) under the given transformation is (12,−1)

Find the image of the point $(- 2, - 7)$ under the transformation
$(x, y) \to (x - 2 y, - 3 x + y) .$

The correct option is A $(12, - 1)$
Given transformation is
$(x, y) \to (x - 2 y, - 3 x + y)$
So, the point $(- 2, - 7)$ $\to (- 2 - 2 (- 7), - 3 (- 2) - 7)$
So, the image of the point $(- 2, - 7)$ under the given transformation is $(12, - 1)$