Find the image of the point (−2,−7) under the transformation (x,y)→(x−2y,−3x+y).
A
(12,−1)
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B
(−12,1)
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C
(2,7)
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D
(−2,7)
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Solution
The correct option is A(12,−1) Given transformation is (x,y)→(x−2y,−3x+y) So, the point (−2,−7)→(−2−2(−7),−3(−2)−7) So, the image of the point (−2,−7) under the given transformation is (12,−1)