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Question

Find the imaginary part of the complex number (1+i)(1i)


A

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B

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C

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Solution

The correct option is C


z = (1+i)(1i)

Taking loge on both sides

log z = (1-i) log(1+i)

= (1-i) loge(2.eiπ4)

= (1-i) [ loge2+logeeiπ4]

= (1-i) [12log2+iπ4]

= 12loge2+iπ4i2loge2+π4

= (12loge2+π4)+i(π412loge2)

Imaginary part of Z {Im(z)} = π4log2


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