Question

Find the inclination of the line ( in degrees ) whose slope is $\frac{1}{\sqrt{3}}$

Answer 1

Slope of a line $m=\tan \theta$, where $\theta$ is the inclination of the line with the x - axis.
Given slope $=\frac{1}{\sqrt{3}}$
$\tan \theta =\frac{1}{\sqrt{3}}$
We know that $tan{30}^0=\frac{1}{\sqrt{3}}$
$=>\theta ={30}^0$
Inclination $={30}^0$