Find the incorrect relation between the stoichiometric coefficients of the following balanced reaction.
$x K_{2} C r_{2} O_{7} + y H I \to z K I + α C r I_{3} + β H_{2} O + γ I_{2}$

y = z + α + β + γ

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β = z + α + γ

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γ = z + α - x

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y = β - x

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Solution

The correct option is D $y = β - x$
The balanced chemical reaction is:
$K_{2} C r_{2} O_{7} + 14 H I \to 2 K I + 2 C r I_{3} + 7 H_{2} O + 3 I_{2}$
From here,
$x = 1, y = 14, z = 2, α = 2, β = 7, γ = 3$
(a) $y = z + α + β + γ$
$\Rightarrow 14 = 2 + 2 + 7 + 3$
(b) $β = z + α + γ$
$\Rightarrow 7 = 2 + 2 + 3$
(c) $γ = z + α - x$
$\Rightarrow 3 = 2 + 2 - 1$
(d) $y = β - x$
$\Rightarrow 14 \neq 7 - 1$
Option (d) is the answer.

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