Question

Find the increase in pressure required to decrease volume of mercury by $0.001\%$. (Bulk modulus of mercury = $2.8\times {10}^{10}N/m^2$)

Answer 1

$B=2.8\times {10}^{10}$
$\Delta V_{2}0.001\%$
$v\times \frac{0.001}{100}=0v$
$\therefore \frac{0v}{=0.00001v}$
$\therefore B=\frac{pv}{\Delta v}$
$\therefore 2.8\times {10}^{10}\times {10}^{-5}=P$
$\therefore 2.8\times {10}^{5}N/m^2$