Find the indicated terms in the sequence, whose $n^{t h}$ term is: $a_{n} = 4 n - 3; a_{17}, a_{24}$ .

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Solution

Finding $a_{17}$ and $a_{24}$ terms of sequence.
Given, $a_{n} = 4 n - 3$
Substituting $n = 17$ in $a_{n}$ , we get
$a_{17} = 4 \times 17 - 3$
$\Rightarrow a_{17} = 68 - 3 = 65$

Now, put $n = 24$ in $a_{n}$ , we get
$a_{24} = 4 \times 24 - 3$
$\Rightarrow a_{24} = 96 - 3 = 93$

Hence, the values of $a_{17}$ and $a_{24}$ terms are $65$ and $93$ respectively.

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